[PEAK] tools.server.url

[Wayne Larsen]

On 19-Oct-04, at 2:18 PM, Bob Ippolito wrote:

> On Oct 19, 2004, at 15:50, Phillip J. Eby wrote:
>
>> Also, I'm surprised that using port 0 doesn't work to allocate an 
>> available port.  That almost seems to me like something's broken in 
>> OS/X, but maybe it's a general BSD thing.  (Ty: any thoughts on that? 
>>  Bob?)
>
> It works on OS X 10.3.. I don't know why it doesn't work in his 
> application.
>
> >>> import socket
> >>> sockets = socket.getaddrinfo(None, 0, 0, socket.SOCK_STREAM, 0, 
> socket.AI_PASSIVE)
> >>> sockets
> [(30, 1, 6, '', ('::', 0, 0, 0)), (2, 1, 6, '', ('0.0.0.0', 0))]
> >>> for (af, socktype, proto, canonname, sa) in sockets:
> ...     s = socket.socket(af, socktype, proto)
> ...     s.bind(sa)
> ...     s.listen(5)
> ...     print s.getsockname()
> ...
> ('0.0.0.0', 53591, 0, 0)
> ('0.0.0.0', 53592)
> >>>
>
I tried your example, and it worked fine.  Upon examination, the 
difference seems to be in the socket type  and protocol that are coming 
in.  When I set the socket url to: 'tcp://127.0.0.1:8000', the socket 
type and protocol come in as 1 and 6 respectively.  However, when the 
socket url is 'tcp://127.0.0.1:0', the socket type and protocol are 
coming in as 0 and 0.  The socket type of 0 is what is throwing the 
exception that I was seeing.

Note that localhost also doesn't work for me (where explicitly using 
127.0.0.1 does, but that may be an issue in my config?

Hope that helps,
Wayne